100 ml of a solution containing 5 g of NaOH are mixed with 200 ml of M/5 NaOH solution. Calculate the molarity of the resulting solution.
100 ml of a solution containing 5 g of NaOH are mixed with 200 ml of M/5 NaOH solution. Calculate the molarity of the resulting solution.
Answer:
Given Values
Solution – A
V1 = 200 ml
M1 = 1/5 = 0.2
Solution – B
V2 = 100 ml
MB = NaOH = 23+16+1 = 40
M2 = \( \frac{W_{B} \times 1000}{M_{B} \times V_{sol}} \) = 1.25
Calculate
Molarity of final solution formed after mixing both solution ‘A’ and solution ‘B’:
\( M_{mix} = \frac{M_{1}V_{1}+M_{2}V_{2}}{V_{1}+V_{2}} \)
\( M_{mix} = \frac{\left ( 0.2 \times 200 \right )+ \left ( 1.25 \times 100 \right )}{200~+~100} \)
Mmix = 0.55 mol/L
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