# 100 ml of a solution containing 5 g of NaOH are mixed with 200 ml of M/5 NaOH solution. Calculate the molarity of the resulting solution.

100 ml of a solution containing 5 g of NaOH are mixed with 200 ml of M/5 NaOH solution. Calculate the molarity of the resulting solution.

Given Values

Solution – A

V1 = 200 ml

M1 = 1/5 = 0.2

Solution – B

V2 = 100 ml

B = NaOH = 23+16+1 = 40

M2 = $$\frac{W_{B} \times 1000}{M_{B} \times V_{sol}}$$ = 1.25

Calculate

Molarity of final solution formed after mixing both solution ‘A’ and solution ‘B’:

$$M_{mix} = \frac{M_{1}V_{1}+M_{2}V_{2}}{V_{1}+V_{2}}$$

$$M_{mix} = \frac{\left ( 0.2 \times 200 \right )+ \left ( 1.25 \times 100 \right )}{200~+~100}$$

Mmix = 0.55 mol/L