A solid AB has NaCl structure. If the radius of cation A is 110 pm, what is the possible radius of anion B ?
A solid AB has NaCl structure. If the radius of cation A is 110 pm, what is the possible radius of anion B ?
Answer:
Given Values
Radius of Cation (r+) = 110 pm
Structure of Solid = NaCl type
NaCl type Means: The radius ratio is between 0.414 – 0.732
Calculations
\( \frac{Radius~of~Cation}{Radius~of~Anion} \) = 0.414 to 0.732
Calculate the maximum possible radius of Anion ‘B’
\( \frac{110}{Radius~of~Anion}=0.414 \)
\( Radius~of~Anion = \frac{110}{0.414} \) = 365.7 pm
Calculate the minimum possible radius of Anion ‘B’
\( \frac{110}{Radius~of~Anion}=0.732 \)
\( Radius~of~Anion = \frac{110}{0.732} \) = 150.27 pm
Therefore, the possible radius of anion ‘B’ is 150.27 pm to 365.7 pm
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