Battery acid is 4.27 M H2SO4 and has density of 1.25 g/ml. What is the molality of H2SO4 in the solution?
Battery acid is 4.27 M H2SO4 and has density of 1.25 g/ml. What is the molality of H2SO4 in the solution?
Answer:
Given Values
Molarity = 4.27 mol/L
MB = H2SO4 = 2(1)+32+4(16) = 98
Dsol = 1.25 gm/ml
Calculate
Molality = \( \frac{Molarity \times 1000}{\left ( D_{sol} \times 1000 \right )-\left ( Molarity \times M_{B} \right )} \)
Molality = \( \frac{4.27 \times 1000}{\left ( 1.25 \times 1000 \right )-\left ( 4.27 \times 98 \right )} \)
Molality = 5.135 mol/Kg
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