# Battery acid is 4.27 M H2SO4 and has density of 1.25 g/ml. What is the molality of H2SO4 in the solution?

Battery acid is 4.27 M H2SO4 and has density of 1.25 g/ml. What is the molality of H2SO4 in the solution?

Given Values

Molarity = 4.27 mol/L

MB = H2SO4 = 2(1)+32+4(16) = 98

Dsol = 1.25 gm/ml

Calculate

Molality = $$\frac{Molarity \times 1000}{\left ( D_{sol} \times 1000 \right )-\left ( Molarity \times M_{B} \right )}$$

Molality = $$\frac{4.27 \times 1000}{\left ( 1.25 \times 1000 \right )-\left ( 4.27 \times 98 \right )}$$

Molality = 5.135 mol/Kg