# Calculate the molality of a solution containing 20.7 g of K2CO3 dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml)

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Calculate the molality of a solution containing 20.7 g of K2CO3 dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml), class 12 chemistry question and answer, solutions

**Calculate the molality of a solution containing 20.7 g of K _{2}CO_{3 }dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml) **

**Answer:**

**Given Values**

W_{B} = 20.7 gm

M_{B} = K_{2}CO_{3} = 2(39)+12+3(16) = 138

D_{sol} = 1 gm/ml

V_{sol} = 500 ml

∴ W_{sol} = D_{sol} × V_{sol} = 500 gm

**Calculate**

molality = \( \frac{W_{B} \times 1000}{M_{B}~\left ( W_{sol}-W_{B} \right )} \)

molality = \( \frac{20.7 \times 1000}{138~\left ( 500-20.7 \right )} \)

**molality = 0.313 mol/kg**

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