Calculate the molality of a solution containing 20.7 g of K2CO3 dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml)
Calculate the molality of a solution containing 20.7 g of K2CO3 dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml)
Answer:
Given Values
WB = 20.7 gm
MB = K2CO3 = 2(39)+12+3(16) = 138
Dsol = 1 gm/ml
Vsol = 500 ml
∴ Wsol = Dsol × Vsol = 500 gm
Calculate
molality = \( \frac{W_{B} \times 1000}{M_{B}~\left ( W_{sol}-W_{B} \right )} \)
molality = \( \frac{20.7 \times 1000}{138~\left ( 500-20.7 \right )} \)
molality = 0.313 mol/kg
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