# Calculate the molality of a solution containing 20.7 g of K2CO3 dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml)

Calculate the molality of a solution containing 20.7 g of K2CO3 dissolved in 500 mL of the solution (assuming density of solution = 1 g/ml)

Answer:

Given Values

WB = 20.7 gm

MB = K2CO3 = 2(39)+12+3(16) = 138

Dsol = 1 gm/ml

Vsol = 500 ml

∴  Wsol = Dsol × Vsol = 500 gm

Calculate

molality = $$\frac{W_{B} \times 1000}{M_{B}~\left ( W_{sol}-W_{B} \right )}$$

molality = $$\frac{20.7 \times 1000}{138~\left ( 500-20.7 \right )}$$

molality = 0.313 mol/kg

### You should check out our other content to boost your self-study.

• You can read and download our notes
• You can practice multiple choice questions.
• You can practice short and long answer questions
• You can watch our pre-recorded video lectures.
• You can participate in multiple choice questions quiz.