Calculate the number of atoms in a cubic based unit cell having one atom on each corner and two atoms on each body diagonal.
Calculate the number of atoms in a cubic based unit cell having one atom on each corner and two atoms on each body diagonal.
Answer:
Count the number of atoms on corner
Part of atom on each corner = 1/8
Total number of atoms on cube corner = 8 × 1/8 = 1 atom
Count the number of atoms on body diagonal
Total body diagonal = 4
Atoms on each body diagonal = 2
Part of atom on body diagonal = complete (1)
Total number of atoms on body diagonal = 4 × 2 = 8 atoms
Therefore, total number of atoms in cubic unit cell = 1 + 8 = 9 atoms
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