One litre solution of N/2 HCl is heated in a beaker. It was observed that when the volume of the solution is reduced to 600 mL, 3.25 g of HCl is lost. Calculate the normality of the new solution.
One litre solution of N/2 HCl is heated in a beaker. It was observed that when the volume of the solution is reduced to 600 mL, 3.25 g of HCl is lost. Calculate the normality of the new solution.
Answer:
Given Values
Initial Solution
VSol = 1 L or 1000 ml
Normality = 1/2 or 0.5 gm.eq./L
MB = HCl = 1+35.5 = 36.5
Number of H+ = 1
Solution after Heating
VSol = 650 mL
Lost weight of HCl = 3.25 gm
Calculations
Weight of solute (HCl) in initial solution.
WB = \( \frac{Normality \times M_{B} \times V_{Sol~in~L}}{H^{+}} \)
WB = \( \frac{0.5 \times 36.5 \times 1}{1} \) = 18.25 gm
Weight of solute (HCl) left in solution after heating:
WB = 18.25 – 3.25 = 15 gm
Normality of solution after Heating
Normality = \( \frac{W_{B} \times 1000 \times H^{+}}{M_{B} \times V_{Sol~in~ml}} \)
Normality = \( \frac{15 \times 1000 \times 1}{36.5 \times 600} = \frac{150}{219} \)
Normality = 0.685 gm.eq./L
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