# One litre solution of N/2 HCl is heated in a beaker. It was observed that when the volume of the solution is reduced to 600 mL, 3.25 g of HCl is lost. Calculate the normality of the new solution.

**One litre solution of N/2 HCl is heated in a beaker. It was observed that when the volume of the solution is reduced to 600 mL, 3.25 g of HCl is lost. Calculate the normality of the new solution.**

**Answer:**

**Given Values**

**Initial Solution**

V_{Sol} = 1 L or 1000 ml

Normality = 1/2 or 0.5 gm.eq./L

M_{B} = HCl = 1+35.5 = 36.5

Number of H^{+} = 1

**Solution after Heating**

V_{Sol} = 650 mL

Lost weight of HCl = 3.25 gm

**Calculations**

**Weight of solute (HCl) in initial solution.**

W_{B} = \( \frac{Normality \times M_{B} \times V_{Sol~in~L}}{H^{+}} \)

W_{B} = \( \frac{0.5 \times 36.5 \times 1}{1} \) = 18.25 gm

**Weight of solute (HCl) left in solution after heating:**

W_{B} = 18.25 – 3.25 = 15 gm

**Normality of solution after Heating**

Normality = \( \frac{W_{B} \times 1000 \times H^{+}}{M_{B} \times V_{Sol~in~ml}} \)

Normality = \( \frac{15 \times 1000 \times 1}{36.5 \times 600} = \frac{150}{219} \)

**Normality = 0.685 gm.eq./L**

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