Sodium crystallizes in a BCC unit cell. Calculate the approximate number of unit cells in 8.6 g of the sodium (atomic mass of Na = 23)
Sodium crystallizes in a BCC unit cell. Calculate the approximate number of unit cells in 8.6 g of the sodium (atomic mass of Na = 23)
Answer:
Given Values
Type of unit cell = BCC
So, 1 U.C. is made up of = 2 atoms
Atomic Mass of sodium = 23 gm/mol
Weight of sodium = 8.6 gm
Calculations
Number of atoms in 8.6 gm of Sodium
23 gm of Sodium = 6.02 × 1023 atoms of Sodium
8.6 gm of Sodium = \( \frac{6.02 \times 10^{23} \times 8.6}{23} \) atoms
Number of U.C. in 8.6 gm of Sodium
2 atoms of Sodium = 1 Unit Cell
\( \frac{6.02 \times 10^{23} \times 8.6}{23} \) atoms = \( \frac{6.02 \times 10^{23} \times 8.6}{23 \times 2} \) U.C.
Therefore, there are \( 1.125 \times 10^{23} \) unit cells in 8.6 gm of Sodium.
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