The compound CuCl has FCC structure like ZnS. Its density is 3.4 g cm-3. What is the length of the edge of the unit cell?
The compound CuCl has FCC structure like ZnS. Its density is 3.4 g cm-3. What is the length of the edge of the unit cell?
Answer:
Given Values
Density = 3.4 gm/cm3
Formula mass (M) = CuCl = 63.5+35.5=99
CuCl has FCC unit cell. So, Z = 4
Avogadro Number (NA) = 6.02 × 1023
Formula used : \( D=\frac{Z \times M}{\left ( a \right )^{3}\times N_{A}} \)
Calculations
Let us find the edge length (a) using the density of the unit cell
\( \left ( a \right )^{3}=\frac{Z \times M}{D \times N_{A}} \)
\( \left ( a \right )^{3}=\frac{4 \times 99}{3.4 \times 6.02 \times 10^{23}} \) = 193.45 × 10-24 cm3
a = 5.783 × 10-8 cm = 578.3 pm
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