Xenon crystallizes in face-centered cubic lattice and the edge of the unit cell is 620 pm. What is the nearest neighbour distance and what is radius of xenon atom?
Xenon crystallizes in face-centered cubic lattice and the edge of the unit cell is 620 pm. What is the nearest neighbour distance and what is radius of xenon atom?
Answer:
Given Values
Edge length (a) = 620 pm
Type of Unit Cell = FCC
As we know the relation between edge length (a) and distance (d) between two nearest atoms for FCC is
\( d=\frac{a}{\sqrt{2}} \)
Calculations
Calculate the nearest neighbour distance (d)
\( d= \frac{a}{\sqrt{2}} = \frac{620~pm}{1.414} \) = 438.47 pm
Calculate the radius (r) of atom
\( r= \frac{d}{2}= \frac{438.47~pm}{2} \) = 219.24 pm
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